16(b) Method 1, using Algebraic Method

Find the

**smallest**possible value of the

**whole number w if 432w is a multiple of 324.**

Note that

**if 432w is a multiple of 324,**we can express it as

432w = 324 x A where A is the factor, when multiply by 324 will give a number that is 432xw

In part (a), we know that 324 = 2 x 2 x 3 x 3 x 3 x 3

and 432 = 2 x 2 x 2 x 2 x 3 x 3 x 3

Then, we can rewrite

2 x 2 x 2 x 2 x 3 x 3 x 3 x w = 2 x 2 x 3 x 3 x 3 x 3 x A

Simplifying, we get

2 x 2 x w = 3 x A

Hence, 4 x w = 3 x A

the smallest number that we could have for w and A such that both sides are the same would be:

when w = 3 and A = 4.

Hence, w = 3

16(b) By listing and comparison

so basically this i something like algebra right?so different from mac spicy's explanation...

ReplyDeletelovylim

Hi Lovy

ReplyDeleteYes, slightly different.

I've introduced simple algebra in this.

However, at the beginning, I made use of the product of factors to simplify the equation.